Let (x) = distance of (m_1) below axle. Then (m_2) is at height (l - x) (if total string length = constant (l)). (T = \frac12 m_1 \dotx^2 + \frac12 m_2 \dotx^2 = \frac12 (m_1+m_2)\dotx^2).
| | Bad solution | |------------------|------------------| | States chosen generalized coordinates clearly. | Only final EoM, no derivation. | | Shows ( T ) and ( V ) separately. | Skips steps in differentiation. | | Includes simplifications (small-angle, equilibrium points). | Ignores constraints or overcounts DOF. | | Checks dimensions and limits. | No physical interpretation. | lagrangian mechanics problems and solutions pdf
Visuals showing how the generalized coordinates are defined. Let (x) = distance of (m_1) below axle